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3#
發(fā)表于 2012-6-16 12:38:59
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本帖最后由 anthonywang9 于 2012-6-16 12:40 編輯
試試這個
SELECT *
FROM
(SELECT ID as 組合ID,學(xué)校 as 組合學(xué)校,代碼 as 組合代碼
from 學(xué)校
union
SELECT [a.ID]&[b.ID] AS 組合ID, [a.學(xué)校]&";"&[a.代碼]&";"&[b.學(xué)校]&";"&[b.代碼] AS 組合學(xué)校, [a.代碼]&"/"&[b.代碼] AS 組合代碼
FROM 學(xué)校 AS a, 學(xué)校 AS b
WHERE a.ID<b.ID
union
SELECT [a.ID]&[b.ID]&[c.ID] AS 組合ID, [a.學(xué)校]&";"&[a.代碼]&";"&[b.學(xué)校]&";"&[b.代碼]&";"&[c.學(xué)校]&";"&[c.代碼] AS 組合學(xué)校, [a.代碼]&"/"&[b.代碼]&"/"&[c.代碼] AS 組合代碼
FROM 學(xué)校 AS a, 學(xué)校 AS b, 學(xué)校 AS c
WHERE a.ID<b.ID and b.id<c.ID
union
SELECT [a.ID]&[b.ID]&[c.ID]&[d.ID] AS 組合ID, [a.學(xué)校]&";"&[a.代碼]&";"&[b.學(xué)校]&";"&[b.代碼]&";"&[c.學(xué)校]&";"&[c.代碼]&";"&[d.學(xué)校]&";"&[d.代碼] AS 組合學(xué)校, [a.代碼]&"/"&[b.代碼]&"/"&[c.代碼]&"/"&[c.代碼] AS 組合代碼
FROM 學(xué)校 AS a, 學(xué)校 AS b, 學(xué)校 AS c, 學(xué)校 AS d
WHERE a.ID<b.ID and b.id<c.ID and c.id<d.ID) AS [%$##@_Alias]
ORDER BY cint([組合ID]); |
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